Question

What are the y-intercept and the slope of the graph of the following equation? 3x+4y=12

Answer 1

`3x+4y=12\implies 4y=-3x+12\implies y=\cfrac{-3x+12}{4} \\\\\\ y = \cfrac{-3x}{4}+\cfrac{12}{4}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{4}}x+\stackrel{\stackrel{b}{\downarrow }}{3}\qquad \impliedby \begin{array}ll \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}`