Answer:
The equation of the line is 2x - 3y = 9
Explanation:
Given:
Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (3, -1)
Solve:
- The line is parallel to the line 2x - 3y = 5
⇒ the slope of the line = the slope of the line 2x - 3y = 5
- Rearrange the terms of the equation to be in the form
⇒ y = mx + c to find the slope of it
2x - 3y = 5 → subtract 2x from both sides
-3y = 5 - 2x ⇒ divide two sides by -3
y = 5/-3 - 2x/-3 ⇒ y = 2/3 x - 5/3
The slope of the line is 2/3
Given that: The line passes through point (3, -1)
Lets use the rule to find the equation of the line:
y - (-1)/x - 3 = 2/3
y + 1/x - 3 = 2/3 ⇒ by using cross multiplication
3(y + 1) = 2(x - 3) ⇒ open the brackets
3y + 3 = 2x -6 ⇒ put x and y on one side
2x - 3y = 3 + 6
2x - 3y = 9
The equation of the line is 2x - 3y = 9
~Kavinsky