Question

Hydrochloric acid reacts with sodium hydroxide according to the equation:

NaOH + HCl 2 NaCl + H2O
25 cm of NaOH was neutralized by 26 25 cm of 0 1 mol/dm HCI
a
Calculate how many moles of HCI was neutralized
b
Calculate how many moles of NaOH was neutralized.
Calculate the concentration of the NaOH used​

Answer 1

Step-by-step explanation:

Hydrochloric acid reacts with sodium hydroxide according to the equation:

NaOH + HCl ------> NaCl + H2O

25 cm of NaOH was neutralized by 26. 25 cm^3 of a 0.1 M solution of HCl.

Calculate how many moles of HCI was neutralized

if 1 liter of the HCl has 0.1 moles, 100 ml has 0.01 moles

so 26.25 ml has 0.01 X26.25/100 moles or 0.002625 moles

b

Calculate how many moles of NaOH was neutralized. the reaction is 1:1

so 0.002625 moles of NaOH were reacted.

Calculate the concentration of the NaOH used​

25 ml of NaOH were used so the concentration was

(0.002625/25) x 10^3=0.000101X1000 =0.105 MOLES/LITER