Answer:
Step-by-step explanation:
Hydrochloric acid reacts with sodium hydroxide according to the equation:
NaOH + HCl ------> NaCl + H2O
25 cm of NaOH was neutralized by 26. 25 cm^3 of a 0.1 M solution of HCl.
Calculate how many moles of HCI was neutralized
if 1 liter of the HCl has 0.1 moles, 100 ml has 0.01 moles
so 26.25 ml has 0.01 X26.25/100 moles or 0.002625 moles
b
Calculate how many moles of NaOH was neutralized. the reaction is 1:1
so 0.002625 moles of NaOH were reacted.
Calculate the concentration of the NaOH used
25 ml of NaOH were used so the concentration was
(0.002625/25) x 10^3=0.000101X1000 =0.105 MOLES/LITER