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Find the function f whose zeros are 6 and 3

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f(x) = x^2 - 9x + 18

To find the zeroes of a function f, use the fact that they make f(x) = 0. So, in this case, f(x) = (x-a)(x-b), for a and are the zeroes of the function. So:

f(x) = (x - 3)(x - 6) = x^2 - 9x + 18
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