Question

A stone is dropped from a high cliff vertically. After 6

seconds, it hits the ground. How high is the cliff?
Please determine which of the following equations
is the best choice to solve this problem.
v² = v.2 + 2aAy
f

V₁
f= V₁ + gt

Ay=v₂t + ½ gt2
Ay = ¹/2(v₁ + v)t

Answer 1

Ay=v₂t + ½ gt² is the best choice to solve this problem.

The height of the cliff is = 176.4 meters.

Step-by-step explanation:

Given,

initial velocity = 0m/s as it is dropped vertically

acceleration = g = 9.8 m/s²

time = 6s

Height =?

Using the equation Ay=v₂t + ½ gt², we can calculate Ay, which is the height.

So,

Ay=v₂t + ½ gt²

by substituting v, t, and g, we get:

Ay= 0 × 6 + ½ × 9.8 × 6²

Ay = 0 + 4.9 × 36

Ay = 176.4 m