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5 votes
How many solutions does the equation have?

How many solutions does the equation have?-example-1
User Brett Bender
by
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2 Answers

19 votes
19 votes

Answer:

All real numbers are solutions.

Explanation:

4(z−5)+2=4z−18

Step 1: Simplify both sides of the equation.

4(z−5)+2=4z−18

(4)(z)+(4)(−5)+2=4z+−18(Distribute)

4z+−20+2=4z+−18

(4z)+(−20+2)=4z−18(Combine Like Terms)

4z+−18=4z−18

4z−18=4z−18

Step 2: Subtract 4z from both sides.

4z−18−4z=4z−18−4z

−18=−18

Step 3: Add 18 to both sides.

−18+18=−18+18

0=0

User AndrewD
by
3.2k points
14 votes
14 votes

Answer:

Infinitely many

Explanation:

They both equal the same equation

User Krikara
by
2.6k points