Question

A 750g block of Iron was heated using 0.75KJ of energy of the starting temperature was 21°C what was the final temperature?​

Answer 1

23.2 °C

Step-by-step explanation:

Specific heat of iron is .449 J / (g-C) .75kj = 750 j

750 j / 750 g (x) = .449 where x is the C degree change from 21 °C

750 / (750 *.449) = x x = 2.2 degrees C

21 C + 2.2 degrees C = 23.2

Answer 2

The temperature is 75°

Step-by-step explanation:

Becauuse the Iron was still heating so.. it reached 75° C