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Given (6,-2) and parallel to y=3/2x+7
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Given (6,-2) and parallel to y=3/2x+7

User Florakel
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Answer: y=(3/2)x-11

Explanation:


\displaystyle\\(6,-2)\ \ \ \ y=(3)/(2)x+7 \\y=mx+b\\m=(3)/(2) \ \ \ \ (6,-2)\\Hence,\\-2=(3)/(2)(6)+b \\\\-2=(3(6))/(2) +b\\\\-2=(18)/(2)+b\\\\-2=9+b\\\\-2-9=9+b-9\\\\-11=b\\\\Thus,\ b=-11\\\\y=(3)/(2) x-11

User Zadr
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