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Solving Inequalities
8(n+4)+3n≥2(n-2)
pls show work

1 Answer

4 votes
Simplify both sides of the inequality
8(n+4)+3n>=2(n-2)
You would get
11n+32>=2n-4
Step 2: Subtract 2n from both sides
11n+32-2n >= 2n-4-2n
Answer: 9n+32>=-4
Step 3: Subtract 32 from both sides
9n+32-32 >= -4-32
Step 4: Divide both sides by 9
9n/ >= -36/9
Whole answer: n >= -4
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