Question

N Exercises 1-4, assume that and y are both differential anctions of t and find the required values of dy/dt and dx/dt.

y = 2(x² – 3x)

find
dy/dt when x=3

given
dx/dt=2
​

Answer 1

dy/dt = 12.

Explanation:

y = 2(x² – 3x)

y = 2x^2 - 6x

dy/dt = 2*2x* dx/dt - 6 dx/dt

= 4x dx/dt - 6 dx/dt

When x = 3 and dx/dt = 2

dy/dt = 4*3*2 - 6*2

= 12.