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Please help me on this it’s due

Please help me on this it’s due-example-1
User Jon Sud
by
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1 Answer

14 votes
14 votes

Answer: 5 cakes

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Step-by-step explanation:

Let's start off converting the mixed number 12 & 1/4 to an improper fraction.


a (b)/(c) = (a*c+b)/(c)\\\\12 (1)/(4) = (12*4+1)/(4)\\\\12 (1)/(4) = (49)/(4)\\\\

Do the same for the other mixed number 2 & 1/3.


a (b)/(c) = (a*c+b)/(c)\\\\2 (1)/(3) = (2*3+1)/(3)\\\\2 (1)/(3) = (7)/(3)\\\\

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From here, we divide the two fractions. I converted them to improper fractions to make the division process easier.


(49)/(4) / (7)/(3) = (49)/(4) * (3)/(7)\\\\(49)/(4) / (7)/(3) = (49* 3)/(4* 7)\\\\(49)/(4) / (7)/(3) = (7* 7* 3)/(4* 7)\\\\(49)/(4) / (7)/(3) = (7* 3)/(4)\\\\(49)/(4) / (7)/(3) = (21)/(4)\\\\

The last step is to convert that result to a mixed number.


(21)/(4) = (4*5+1)/(4)\\\\(21)/(4) = (4*5)/(4)+(1)/(4)\\\\(21)/(4) = 4+(1)/(4)\\\\(21)/(4) = 5 (1)/(4)\\\\

Note that 21/4 = 5.25 and 1/4 = 0.25 to help check the answer.

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Therefore, she can make 5 cakes. The fractional portion 1/4 is ignored since we're only considering whole cakes rather than partial ones.

User Dmodulus
by
2.4k points
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