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The table shows the purchases of two customers at a concession stand at the basketball game. Hamburgers Drinks Total Cost Customer 1 2 $13.00 Customer 2 3 7 $21.00 You want to buy 8 drinks and 9 hamburgers for you and your friends. How much do you expect to pay?​

The table shows the purchases of two customers at a concession stand at the basketball-example-1
User Bsautner
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1 Answer

10 votes
10 votes


\bold{\huge{\blue{\underline{Solution}}}}


\bold{\underline{ Given :- }}

  • Customer 1 bought 2 hamburgers and 4 drinks at a cost of $13.00
  • Customer 2 bought 3 hamburgers and 7 drinks at a cost of $21.00


\bold{\underline{ To \: Find :- }}

  • We have to find the total cost of 8 drinks and 9 hamburgers


\bold{\underline{ Let's \: Begin :- }}

Let the cost of hamburgers and drinks be x and y

According to the question,


\sf{ 2x + 4y = 13.00 ...eq( 1 ) }


\sf{ 3x + 7y = 21.00 ...eq(2) }

Solving eq( 1 ) we get :-


\sf{ 2x + 4y = 13 }


\sf{ 2x = 13 - 4y }


\sf{ x = (13 - 4y)/2 ...eq(3)}

Subsituting eq(3) in eq( 2 ) :-


\sf{ 3( 13 - 4y)/2 + 7y = 21 }


\sf{ 39 - 12y/2 + 7y = 21 }


\sf{ 39 - 12y + 14y = 42}


\sf{ 2y = 42 - 39 }


\sf{ 2y = 3 }


\sf{ y = 3/2 }

Subsituting value of y in eq(3) :-


\sf{ x = 13 - 4(3/2)/2}


\sf{ x = 13 - 2(3)/2}


\sf{ x = 13 - 6/2}


\sf{ x = 7/2 }

Therefore,


\sf{ Cost\: of \:8 \:drinks}


\sf{ = 8 * 3/2 }


\sf{ = 4 * 3 }


\sf{ = 12.00 dollars}

And


\sf{ Cost\: of \:9 \:hamburgers }


\sf{ = 9 * 7/2 }


\sf{ = 63/2}


\sf{ = 31.50 dollars}

Total cost of the 8 drinks and 9 hamburgers


\sf{ 12.00 + 31.50}


\sf{\red { = 43.50 \:dollars}}

Hence, The total cost paid by you for 8 drinks and 9 hamburgers is $43.50 .

User Rishabh Garg
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