Answer: 13 & 19
Explanation:
Let the bigger number be 'U' and the smaller number 't'.
Since the two numbers have a sum of 32, then U + t = 32.
& since one number is 6 more than the other, the U - 6 = t
⇒ U + U - 6 = 32
2U = 38
U = 19
By substituting fot the value of U we found,
19 - 6 = t
t = 13
∴ the numbers are 13 & 19.