Question

H(-1, 3), X(7, -1) What is the midpoint?

Answer 1

(3, 1 )

Explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

(
`(x_(1)+x_(2) )/(2)` ,
`(y_(1)+y_(2) )/(2)` )

here (x₁, y₁ ) = H (- 1, 3 ) and (x₂, y₂ ) = X (7, - 1 ) , then

midpoint = (
`(-1+7)/(2)` ,
`(3-1)/(2)` ) = (
`(6)/(2)` ,
`(2)/(2)` ) = (3, 1 )