175k views
5 votes
X² + 10x + 17 =0

Solve by completing the sqaure

User Mansur
by
7.5k points

1 Answer

6 votes

Answers:
\text{x} = 5+2√(2) \ \ \text{ or } \ \ \text{x} = 5-2√(2)

===================================================

Step-by-step explanation:

The x coefficient is 10, which divides in half to get 5.

Square this to get 5^2 = 5*5 = 25

We need to add 25 to both sides so that the x² + 10x portion gets to x² + 10x+25 and we can factor it to (x+5)²

Here's what the steps look like when we complete the square.


\text{x}^2 + 10\text{x} + 17 =0\\\\\text{x}^2 + 10\text{x} + 17+25 =0+25\\\\(\text{x}^2 + 10\text{x}+25) + 17 = 25\\\\(\text{x}+5)^2+17 = 25\\\\(\text{x}+5)^2 = 25-17\\\\(\text{x}+5)^2 = 8\\\\

Then we apply the square root to both sides. Don't forget about the plus/minus.


(\text{x}+5)^2 = 8\\\\\sqrt{(\text{x}+5)^2} = √(8)\\\\|\text{x}+5| = √(8)\\\\\text{x}+5 = \pm√(8)\\\\\text{x}+5 = \pm2√(2)\\\\\text{x} = 5\pm2√(2)\\\\\text{x} = 5+2√(2) \ \ \text{ or } \ \ \text{x} = 5+2√(2)\\\\

You can use the quadratic formula to verify the two roots.

User Darrell Root
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.