Answer:
120, 121, 122 and 123
Explanation:
Consecutive integers are separated by a difference of 1
Let the first integer be n
Then the second integer is n + 1
The third integer is n + 2
and the fourth integer is n + 3
Adding these together will give the sum of the 4 integers
n + (n + 1) + (n + 2) + (n + 3) = 486 (given)
n + n + n + n + 1 + 2 + 3 = 486
4n + 6 = 486
4n = 486 - 6
4n = 480
n = 120
So the 4 integers are 120, 121, 122 and 123