DESIGN Find the values of x and y so that PR and QS are perpendicular. 11 P J S (4y-2) (5x+6) ° 2x ° T 4 R

asked May 14, 2023 164k views

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DESIGN Find the values of x and y so that PR and QS are perpendicular.

11
P
J
S
(4y-2)
(5x+6) °
2x °
T
4
R

by Surui

5.3k points

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1 vote

Answer: x=12, y=23

Explanation:

$\angle SQR=\angle SQP=90^(\circ)$ , so:

$4y-2=90\\\\4y=92\\\\y=23\\\\\\\\5x+6+2x=90\\\\7x+6=90\\\\7x=84\\\\x=12$

Hebert answered May 20, 2023

6.1k points

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