Question

DESIGN Find the values of x and y so that PR and QS are perpendicular.

11
P
J
S
(4y-2)
(5x+6) °
2x °
T
4
R

Answer 1

Answer: x=12, y=23

Explanation:

`\angle SQR=\angle SQP=90^(\circ)`, so:

`4y-2=90\\\\4y=92\\\\y=23\\\\\\\\5x+6+2x=90\\\\7x+6=90\\\\7x=84\\\\x=12`