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What is the acetate ion concentration, (C2H3O2^1-), of a 100mL of calcium acetate solution, Ca(C2H3O2)2, with 25.0g dissolved Ca(C2H3O2)2?

User FriskyGrub
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1 Answer

6 votes

Answer: 3.16

Step-by-step explanation:

First, find the molarity of calcium acetate. Change g to mol and mL to L.

The molar mass of calcium acetate is 158.168 g/mol so...

25.0/158.168= 0.158 mol

100 mL is 0.1L (divide by 1000) Divide the moles by the L;

0.158/0.1 = 1.58

This is the molarity of calcium acetate but we want the concentration of just acetate. The chemical formula would be

Ca(C2H3O2)2 -> Ca + 2C2H3O2

meaning for every one mol of calcium acetate, there will be two moles of acetate. Thus, multiply your answer by two to get the molarity/concentration of the acetate.

1.58×2=3.16 M

User Poiana Apuana
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