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Write an equation in point-slope form for the line that satisfies the given set of conditions. slope of − 2/3 , passes through ( 6, − 8 )

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(\stackrel{x_1}{6}~,~\stackrel{y_1}{-8})\hspace{10em} \stackrel{slope}{m} ~=~ - \cfrac{2}{3} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \implies y +8= -\cfrac{2}{3} (x -6)

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