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Solve the inequality: x+10>2x/5. *

User Kraylog
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Hello BATAPAAKO!


\huge \boxed{\mathbb{QUESTION} \downarrow}

Solve the inequality: x+10>2x/5.


\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}


x + 10 \gt \frac { 2 x } { 5 } \\

Firstly, multiply both sides of the equation by 5.


5(x + 10) > 2x \\ = 5x + 50 > 2x

Since 5 is greater than 0, the direction of the inequality will remain unchanged. Now, subtract 2x from both the sides.


5x + 50 > 20 \\ = 5x + 50 - 2x > 0

Combine 5x & -2x to get 3x.


5x + 50 - 2x > 0 \\ = 5x - 2x + 50 > 0 \\ = 3x + 50 > 0

Now, subtract 50 from both the sides. Remember :- anything subtracted by 0 will result in its negation. So 50 subtracted from 0 will give you -50.


3x + 50 > 0 \\ = 3x > - 50

Divide both sides of the equation by 3. Again, since 3 is > 0, the direction of inequality will remain unchanged.


3x > - 50 \\ = \large\boxed{\boxed{ \bf \: x > - ( 50)/(3) }}

__________________

Hope it'll help you!

ℓucαzz ッ

User Viktors Telle
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