Answer:
Explanation:
We choose arbitrary values for x and in each case calculate y = 2x + 5.
If x = 0, y = 5; if x = 3, y = 11, and so on.
How? when x = 3, y = 2(3) + 5 = 6 + 5 = 11.
The table, with rows and columns suitable to this problem, would look like:
x y
0 5
3 11
10 25
and so on