Question

What would be the 125th term in the following arithmetic sequence: 6, 8, 10, 12…

Answer 1

a₁₂₅ = 254

Explanation:

the nth term of an arithmetic sequence is

`a_(n)` = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

here a₁ = 6 and d = a₂ - a₁ = 8 - 6 = 2 , then

a₁₂₅ = 6 + (124 × 2) = 6 + 248 = 254