18.5k views
1 vote
Which equation represents a line that passes through (–9, –3) and has a slope of –6? a y – 9 = –6(x – 3) b y + 9 = –6(x + 3) c y – 3 = –6(x – 9) d y + 3 = –6(x + 9)

2 Answers

3 votes

Slope intercept form of line -


y - y_1 = m(x - x_1)

y1 = y - coordinate of point

x1 = x - coordinate of point

m = slope of line


  • y -(- 3) = - 6(x - (- 9))

  • y + 3 = - 6(x + 9)

  • y + 3 = - 6x - 54

  • y + 6x = - 54 - 3

  • y + 6x = - 57

  • 6x + y + 57 = 0

Correct option is : -

D. y + 3 = -6(x + 9)

User Visnu
by
8.2k points
5 votes

Answer:


\textsf{d)} \quad y+3=-6(x+9)

Explanation:

Point-slope form of a linear equation:


\boxed{y-y_1=m(x-x_1)}

Where:

  • m is the slope.
  • (x₁, y₁) is a point on the line.

Given information:

  • Slope = -6
  • Point = (-9, -3)

Substitute the given values into the formula:


\begin{aligned}y-y_1 & =m(x-x_1)\\\implies y-(-3) & =-6(x-(-9))\\y+3 & =-6(x+9)\end{aligned}

Therefore, the equation that represents a line that passes through (-9, -3) and has a slope of -6 is:


\boxed{y+3=-6(x+9)}

User Rlamoni
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories