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In one state, 76% of adults have health insurance. If 5 adults are selected at random from
this state, what is the probability that at least one person does not have health insurance?

User Stephen C
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1 Answer

2 votes

Answer: 0.7464474624

Round this value however your teacher instructs.

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Step-by-step explanation:

(0.76)^5 = 0.2535525376 is the probability of getting all five people having insurance. Each selection is independent.

1 - 0.2535525376 = 0.7464474624 is the probability at least one person doesn't have health insurance.

The events "all 5 have insurance" and "at least one doesn't have insurance" are complementary. Their probabilities add to 1. Either one or the other event must happen, but both cannot happen simultaneously.

User Arcadian
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