Question

An engineer wants to calculate how high a rocket starting from rest will be when it reaches a velocity of 6,500.0 m/s with an acceleration of 389.00 m/s². How high will the rocket be when it meets these conditions?​

Answer 1

See below

Step-by-step explanation:

v = a t

6500 = 389 t shows t = 16.7 s

df = do + vo t + 1/2 at^2

= 0 + 0 + 1/2 (389)(16.7)^2 = 54305.9 m