Question

. How many grams of water would require 4400 joules

of heat to raise its temperature from 34°C to 100°C?
The specific heat of water is 4.18 J/g.C

Answer 1

The specific heat of water is 4.18 J/g C.

Step-by-step explanation:

q

=

m

C

s

Δ

T

Never forget that!

2200

=

m

⋅

4.18

J

g

⋅

°

C

⋅

66

°

C

∴

m

≈

8.0

g