Question

Given h(x) =−x+2, solve for x when h (x)=−3.

Answer 1

`{ \sf{h(x) = - x + 2}}`

For h(x) = -3 implies that -3 is a root of the function h(x)

`{ \sf{h(x) = - x + 2 = - 3}} \\ { \sf{ - x + 2 = - 3}} \\ { \sf{ - x = - 3 - 2}} \\ { \sf{ - x = - 5}} \\ { \sf{x = 5}}`