To find molarity you must divide mole solute/liters of solution
Givens grams of ammonium chloride you can find the moles by diving by it’s molar mass
Ammonium chloride is NH4Cl
14.01(1) + 1.008(4) + 35.45(1) =
53.492 g/mol NH4Cl
23.2 g/53.492 g/mol = 0.434 mol NH4Cl
(this is rounded but I will be using the whole number in the calculations)
You can now divide the moles of HCl by the liters of solution
0.434 mol/.250L = 1.735 M NH4Cl
(You cannot use 250, only .250)
To find the concentration of each ion you multiply the molarity of the whole compound (1.735) by the number of each ion you have
There is only one NH4+ in the compound
And there is only one Cl-, therefore the molarities for the ammonium cation and the chloride cation are the same as the molarity of the solution