Question

Solve for y’ in terms of y and x
y' sin x - x cos x = xy' + y

Answer 1

`{ \tt{y' \sin(x) - x \cos(x) = xy' + y}} \\ \\ { \tt{y' \sin(x) - xy' = y + x \cos(x) }} \\ \\ { \tt{y'( \sin(x) - x) = y + x \cos(x) }} \\ \\ { \boxed{ \tt{ \: y' = (y + x \cos(x) )/( \sin(x) - x ) }}}`