Question

THE TEMPERATURE OF A LIQUID IN AN EXPERIMENT IS 0 C AT 9 AM. THE EXPERIMENT CALLS FOR THE TEMPERATURE TO CHANGE -5/4 C EVERY HOUR. WHAT WILL THE TEMPERATURE BE AT NOON?

Answer 1

Answer: -15/4 or -3 3/4

Explanation:

To solve this problem, you can create an equation:

`T(x) = 0 - (5)/(4)x`

For this equation, we want x to represent the hours passed. We know that noon is three hours after 9AM so we can plug 3 in:

`T(3) = 0 - (5)/(4) * 3 = -(15)/(4)`

I hope this helps, and if you need any more clarification, let me know.