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Question is in picture

Question is in picture-example-1

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Answer: L≈2 m 88 cm 5 mm

Explanation:


\displaystyle\\\boxed {T=2\pi \sqrt{(L)/(g) } }

Divide both parts of the equation by 2π:


\displaystyle\\(T)/(2\pi ) =\sqrt{(L)/(g) }

Squared both parts of the equation:


\displaystyle\\((T)/(2\pi ))^2=(\sqrt{(L)/(g) } )^2\\\\(T^2)/((2\pi )^2) =(L)/(g) \\\\(T^2)/(4\pi ^2) =(L)/(g)

Multiply both parts of the equation by g:


\displaystyle\\(T^2g)/(4\pi ^2) =L\\Thus,\\L=(T^2g)/(4\pi ^2) \\T=3.4\ c\ \ \ \ \ g=9,81 (m)/(c^2) \ \ \ \ \ \pi =3.14\\\\L=((3,4)^2*9.81)/(4*(3.14)^2) \\\\L=(11.56*9.81)/(4*9.86)\\\\ L\approx2.885\ m\\\\L\approx2\ m\ 88\ cm\ 5\ mm

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