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19 votes
19 votes
What is the net force on a cart being pushed with an applied force of 23 N with a frictional force of 23 N? I​

User Superdave
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2 Answers

19 votes
19 votes

Answer:

1N

Step-by-step explanation:

Pretty simple Divide 23 by 23 which gives you 1.

23N ÷ 23N = 1N

User Koningdavid
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3.2k points
21 votes
21 votes

Answer:


\sf \longmapsto \: 1 \: N

Step-by-step explanation:


\sf \longmapsto (23N)/(23N)


\sf \longmapsto1 \: N

User Adamax
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