Question

Determine the mass in grams of 2.89 × 10²¹ atoms of copper. (The mass of one mole of copper is 63.55 g.)

Answer 1

0.30498 g or 0.305 or 3.05 x 10^-1

Step-by-step explanation:

According to Avogadro's number: 1 mole = 6.022 x 10^23 atoms = 63.55 g

so the mass of 2.89 × 10^21 equals

63.55 x (2.89 x 10 ^21)/(6.022 x 10^23)

= (63.55 x 2.89)/6.022 x 10^(21 - 23)

= 30.498 x 10^-2

= 0.30498 g