Question

In the diagram, JL = 140. What is JK? (Round to two decimals if Needed)

Answer 1

• 
  `\sf JK=49.27`

Explanation:

We're given that,

JL = 140

→ → →

*JK + KL = JK*

`\sf 4x+6+7x+15=140`

Let's do the math -

`\sf 4x+6+7x+15=140`

Combine like terms:-

`\sf (4x+7x) = 11x`

`\sf (6+15)=21`

`\sf 11x+21=140`

`\sf 11x+21-21=140-21` ( Subtract 21 from both sides)

`\sf 11x=119`

`\sf \cfrac{11x}{11}=\cfrac{119}{11}` ( Divide both sides by 11)

`\sf x=\cfrac{119}{11}`

→ → →

Now, that we found what x equals, let's find JK:-

*JK = 4x+6*

`\sf 4\left(\cfrac{119}{11}\right)+6`

`\sf JK=49.27`

Therefore, your answer is 49.27!!!

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Hope it helps!

Have a great day!