Question

A motorcycle stunt rider moving horizontally takes off from point 1.25m above the ground landing 10m away. What was the take off speed?

Answer 1

H = 1/2 g t^2 to get time to fall 1.25 m

t = (2 * 1.25 / 9.8)^1/2 = .505 s

Vx t = 10 m

Vx = 10 m / .505 s = 19.8 m/s