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Seattles great wheel travels 175pi ft for each revolution. What is the radius of the Ferris Wheel ?

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\textit{arc's length}\\\\ s = r\theta ~~ \begin{cases} r=radius\\ \theta =\stackrel{radians}{angle}\\[-0.5em] \hrulefill\\ s=175\pi \\ \theta =\stackrel{1~revolution}{2\pi } \end{cases}\implies 175\pi =r(2\pi )\implies \cfrac{175\pi }{2\pi }=r\implies \stackrel{ft}{87.5}=r

User Mgiuffrida
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