Hello there!
Let's solve these equations one by one.
![\boxed{\tt{1}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/5r877ovutxh03tty4pdsl56r80fghlsomd.png)
![\longmapsto\sf{4x-9=9}](https://img.qammunity.org/2023/formulas/mathematics/high-school/wv8lnxgfm7vppr8xin0euxqohcb8l1ndhw.png)
![\longmapsto\sf{4x=-9+9}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ucl8xstbnzxmts4wr5058ew26xt29xnfvs.png)
![\longmapsto\sf{4x=0}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2vyfpu7na5vmsl794b8nzevmevu6lw0im5.png)
![\longmapsto\sf{4x=0}\\\longmapsto\sf{x=0}](https://img.qammunity.org/2023/formulas/mathematics/high-school/g1ppyvegzqt21d9gd6zz89z5ny1zdn26dp.png)
![\dag\quad\bf{Conclusion:}\quad\dag](https://img.qammunity.org/2023/formulas/mathematics/high-school/dldwh9b0tt1ruigx23oty1c91px2b9qz2y.png)
- This equation does have a solution. Let's try the second one.
![\boxed{\tt{2}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/m6hnl9vsab9g0gctonc87o79x6llmr63t7.png)
![\tt{3x+2=17}](https://img.qammunity.org/2023/formulas/mathematics/high-school/4f4lj30jwbplz2d5xu1yi4q49h0c1wqpop.png)
- Subtract 2 from both sides.
![\tt{3x=15}](https://img.qammunity.org/2023/formulas/mathematics/high-school/r7tzoml4qj1fup7p0ki2zkv8vdu84kb92p.png)
![\tt{x=5}](https://img.qammunity.org/2023/formulas/mathematics/high-school/59nd9ueyfcw401yx34oz01sxyifqq9zrgp.png)
![\dag\quad\bf{Conclusion:}\quad\dag](https://img.qammunity.org/2023/formulas/mathematics/high-school/dldwh9b0tt1ruigx23oty1c91px2b9qz2y.png)
- The second equation has a solution as well. Now we need to try the third one:
![\boxed{\tt{3}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/6fal86fl5blzyy6ce9exm69kl8vdv0occf.png)
![\tt{2x+4=2x+6}](https://img.qammunity.org/2023/formulas/mathematics/high-school/y2boqqrefye6j0ra5gddwx49ul3h0o8obb.png)
- Subtract 2x from both sides:
![\tt{2x-2x+4=6}\\\tt{4=6}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ezcpxyi0o8p32sapucvwjtfoe9scqap37a.png)
Uh oh, we've obtained a false statement!
Well as a matter of fact, it was supposed to happen, because you cannot take a number, multiply it times 2, add 4 to that product, then expect it to be equal to that same number times 2, plus 6.
![\stackrel\star{\dag\quad\bf{Conclusion:}\quad\dag}](https://img.qammunity.org/2023/formulas/mathematics/high-school/9vctqpzh9a24op1hv77skp1q0z4eo9dkcr.png)
- So this is the equation that doesn't have a solution!
Therefore, Option C is correct.
I hope this helps, feel free to ask if you have any queries regarding my answer or explanation. I also hope that you'll have a lovely day ahead! :)
![\wp\rm{Rosalia}\wp](https://img.qammunity.org/2023/formulas/mathematics/high-school/z6ta99ur0yri9a1usl2im5kv5qi4b33npl.png)