Question

Given that v²=u²+2as, show that the equation is dimensionally correct​

Answer 1

Step-by-step explanation:

v = final velocity or velocity

ie[M⁰L¹T-¹] meter/second.

and

u= initial velocity or velocity

ie[M⁰L¹T-¹] meter/second

and

a=acceleration [M⁰LT-²]

s= distance [M⁰LT⁰]

then

v²=U²+2as

([M⁰L¹T-¹])²=([M⁰L¹T-¹])²+[M⁰LT-²][M⁰LT⁰] (2 is constant)

[M⁰L²T-²]=[M⁰L²T-²] +[M⁰L²T-²]

HENCE ACCORDING TO LAW OF HOMOGENEITY GIVEN EQUATION IS DIMENSIONALLY CORRECT