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A ball is thrown straight up at an initial velocity of 53 feet per second. In the first 1.5 seconds, it travels 42 feet. The formula X = (u+ t over n) t; represents the vertical distance x that an object travels in 7 seconds, where u represents the initial velocity of the object and n represents the velocity of the object at the end of t seconds. Find the velocity of the ball at the end of 1.5 seconds.



User Tyddlywink
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1 Answer

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Answer:

we know that speed is equal to distance per time

so,

given initial velocity=53 f/s

initial time=1.5 sec

initial distance=42 f

Explanation:

User MKod
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