Given wavelength of X-ray = 4.6 nm
-> λ = 4.6 x 10^-9 m
Energy of X-ray is E_X-ray = h x c / λ
Where h = Planck's constant
-> = 6.626 x 10^-34 Joule * sec
Where c = speed of light/rays
-> = 3 x 10^8 m/s
Where λ = wavelength of X-ray
E_X-ray = ((6.626 x 10^-34) x (3 x 10^8)) / (4.6 x 10^-9)
E_X-ray = 4.321 x 10^-17 Joules
Similarly for given frequency of photon of 9 MHz
Energy of photon is E_radion = h x v
Where v = frequency of photon
-> = 9 x 10^6
E_radio = (6.626 x 10^-34) x (9 x 10^6)
E_radio = 5.963 x 10^-27 Joules
Therefore,
(E_X-ray) / (E_radio) = (4.321 x 10^-17) / (5.963 x 10^-27) = 7.246 x 10^9
This means there is 7.246 x 10^9 times more energy has a 4.6 nm X-ray than a 9 MHz radio photon.