Question

Please help me and I will give you brainiliest!!​

Answer 1

See below

Step-by-step explanation:

Putting in the values of B and C into the acceleration equation gives us this :

2(t^2) - 1/2(- 4) t = 2t^2 +4t

acceleration = a = 2t^2 +2t

Now remember velocity final = a * t

vf = a * t

vf = [2(5^2) +2(5) ] * 5 = 300 m/s

and d = 1/2 a t^2 <====== (for an object starting at rest)

= 1/2 a t^2

= 1/2 ( 2(5^2)+2(5) ) * 5^2 = 55 meters