Question

What is the slope of a line perpendicular to the line whose equation is

3x - 3y = 63. Fully simplify your answer.

Answer 1

perpendicular slope = - 1

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

3x - 3y = 63 ( subtract 3x from both sides )

- 3y = - 3x + 63 ( divide through by - 3 )

y = x + 21 ← in slope- intercept form

with slope m = 1

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(1)` = - 1