Question

Help me with this math problem

Answer 1

`▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪`

Let's solve :

by using Pythagoras theorem :

• EF² = EG² - GF²

• EF² =
  `{\sqrt{}{24}}^(2)` - 3²

• EF² = 24 - 9

• EF² = 15

• EF =
  `{\sqrt{}{15}}`

now,

• 
  `\tan(G) = ( √(15) )/(3)`

• 
  `\tan(G) = (3.873)/(3)`

• 
  `\tan(G) = 1.291`

• 
  `\tan(G) \approx1.29`

Answer 2

tan A = opp

adj

tan G = EF

3

from Pythagoras theorem,

EF² + 3² = (√24)²

EF² + 9 = 24

EF² = 15

EF = √15

then,

tan G = √15

3

therefore tan G = √15/3