Answer:
![{x}^(2) + 2x - 15](https://img.qammunity.org/2023/formulas/mathematics/high-school/mim6wl90ui676ovaepvi5nvvvln0oab93l.png)
Explanation:
Since the roots are 3 & -5, we can write out the factors as binomials:
(x - 3)(x + 5)
If you set both to 0 & solve for x, you will get -5 & 3 as your roots.
From here we can FOIL to get a quadratic equation. Essentially, we are multiplying the first x & -3 by both the second x & 5 to get 4 terms (3 simplified).
This becomes:
![{x}^(2) + 5x - 3x - 15](https://img.qammunity.org/2023/formulas/mathematics/high-school/93maz739bl32h4zh6cvpo44pvv8psljfg7.png)
We can simplify the x to the 1st power terms to get our final equation:
![{x}^(2) + 2x - 15](https://img.qammunity.org/2023/formulas/mathematics/high-school/mim6wl90ui676ovaepvi5nvvvln0oab93l.png)