Answer:
The argument would be valid
Explanation:
Let p = "It is duck season"
Let q = "My name is Bugs Bunny"
The formation would be:
p ∨ q
~ p
∴ ~q
If you made a truth value table, the critical row (means where the premises are true, in this case it would be ~p) has true premise and a true conclusion. Thus the argument is valid.