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Write the equation of the line in slope intercept form that goes through (5,4) and is

parallel to −4x + y = 5

User Jon Brooks
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{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

First, let's find slope of line parallel to required line by converting the equation into slope intercept form :


\qquad \sf  \dashrightarrow \: - 4x + y = 5


\qquad \sf  \dashrightarrow \: y = 4x + 5

So, it's slope is 4 ( Coefficient of x )

Slope of required line is equal to the line parallel to it, so slope of required line is 4 as well.

Now, we have slope : m = 4, and it passes through point (5 , 4) so let's write it's equation in point slope form ~


\qquad \sf  \dashrightarrow \: y - y _ 1 = m(x - x _ 1)


\qquad \sf  \dashrightarrow \: (y -4) = 4(x - 5)


\qquad \sf  \dashrightarrow \: y - 4 = 4x - 20


\qquad \sf  \dashrightarrow \: y = 4x - 20 + 4


\qquad \sf  \dashrightarrow \: y = 4x - 16

User Cplotts
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