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23 votes
23 votes
What is the inverse of:
f(x)=x^3+5

User Ymerej
by
3.0k points

2 Answers

12 votes
12 votes

Answer:

f⁻¹(x) = ∛x-5

Explanation:

y = x³ + 5

x = y³ + 5 ... replace x with y

y³ = x-5

y = ∛x-5

User CaptDaylight
by
2.6k points
17 votes
17 votes

Answer:


\displaystyle \large{ {f}^( - 1) (x) = \sqrt[3]{x - 5} }

Explanation:

To find an inverse, we swap x to f(x)/y and f(x)/y to x.

We are given:-


\displaystyle \large{f(x) = {x}^(3) + 5}

Swap:-

To make the equation look better and easier to simplify, we will be changing f(x) to y.

Thus:-


\displaystyle \large{y= {x}^(3) + 5} \\ \displaystyle \large{x= {y}^(3) + 5}

Now simplify to y-isolated.

Subtract both sides by 5.


\displaystyle \large{x - 5= {y}^(3) + 5 - 5} \\ \displaystyle \large{x - 5= {y}^(3) }

Cube root both sides.


\displaystyle \large{ \sqrt[3]{x - 5} = \sqrt[3]{ {y}^(3) } } \\ \displaystyle \large{ \sqrt[3]{x - 5} = y }

Convert y to f(x) and add exponent of -1 between f and (x).


\displaystyle \large{ \sqrt[3]{x - 5} = {f}^( - 1) (x) }

To indicate that the function is an inverse.

And we're done!

User Sesteva
by
3.2k points