Help mee meee meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

asked Mar 27, 2023 21.2k views

0 votes

by Ajar

7.0k points

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4 votes

Part (a)

f(0)=-0^3+4(0)^2-2(0)+2=2

Part (b)

$f(3)=-3^3+4(3)^2-2(3)+2 \\ \\ =-27+36-6+2 \\ \\ =9-4 \\ \\ =5$

Part (c)

$f(-2)=-(-2)^3+4(-2)^2-2(-2)+2 \\ \\ =8+16+4+2 \\ \\ =30$

Zxeenu answered Apr 2, 2023

6.4k points

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