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The first three terms of a geometric sequence are a,a+14,9a. Find the value of a.​

User Joseville
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1 Answer

4 votes

Answer:

7

Explanation:

The first three terms of a GP are a, ar, ar²

thus we can Equate them to the corresponding terms in the question.

a = a

a+ 14 = ar

9a = ar²

we can simplify the third term to get r

9a = ar² . divide both sides by a

9= r²

thus we square root both sides to get

r = ± 3

thus our r is 3

we insert the value of r in the second term to get a

a + 14 = 3a

14 = 2a

a = 7

User Rosty Kerei
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